Question

Water rises to a height $h$ in a capillary on the surface of the earth in stationary condition. Value of $h$ increases, g decreases then :

• A. On poles
• B. On sun
• C. In a lift going upward with acceleration
• D. In a lift going downward with acceleration

Answer 1

The correct option is D In a lift going downward with acceleration

We have, $h=\frac{2T\cos \theta }{rdg}$

$\Rightarrow h\propto \frac{1}{g}$

When lift moves downwards, then effective value of $g$ decreases, (g-a), hence $h$ increases.