Water rises to a height of 20 mm in a capillary .If the radius of the capillary is one third of its previous value. Then the new value of capillary rise will be

\frac{20}{3}

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60 mm

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\frac{20}{9}

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180 mm

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Solution

The correct option is A 60 mm
Given : $h_{1} = 20 m m$ $r_{1} = r$ $r_{2} = \frac{r}{3}$
Using $h_{1} r_{1} = h_{2} r_{2}$
So, $20 \times r = h_{2} \times \frac{r}{3}$
$⟹ h_{2} = 3 \times 20 = 60 m m$

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Water rises to a height of 20 mm in a capillary .If the radius of the capillary is one third of its previous value. Then the new value of capillary rise will be

The correct option is A 60 mmGiven : h1=20 mm r1=r r2=r3Using h1r1=h2r2So, 20×r=h2×r3⟹ h2=3×20=60 mm

The correct option is A 60 mm
Given : $h_{1} = 20 m m$ $r_{1} = r$ $r_{2} = \frac{r}{3}$
Using $h_{1} r_{1} = h_{2} r_{2}$
So, $20 \times r = h_{2} \times \frac{r}{3}$
$⟹ h_{2} = 3 \times 20 = 60 m m$