Water rises upto a height h in a capillary tube of certain diameter. This capillary tube is replaced by a similar tube of half the diameter. Now the water will rise to the height of:
A
4h
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B
3h
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C
2h
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D
h
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Solution
The correct option is C2h The height h to which the liquid rises in a capillary tube is given by h=2Tcosθrρg ⇒hr= constant
Where, h= height upto which water rises r= radius of capillary tube
Let h′ be the new height
Given: r′=r2 ∴h′r′=hr ⇒h′=hrr′=hrr/2=2h ⇒h′=2h