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Question

Watt per meter kelvin is the unit of

A
Stress
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B
Period of revolution of satellite
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C
Angular displacement
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D
Coefficient of thermal conductivity
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Solution

The correct option is D Coefficient of thermal conductivity
Watt(meter)×(kelvin)=ML2T3LK=MLT3K1
Coefficient of thermal conductivity (k)=(qA)× tdT

(q/A)= heat transfer per unit area(W/m2)

dT= temperature difference
t= thickness

[k]=[ML2T3][L2][L][K]=MLT3K1

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