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Byju's Answer
Standard XII
Physics
Dimensional Analysis
Watt per mete...
Question
Watt per meter kelvin is the unit of
A
Stress
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B
Period of revolution of satellite
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C
Angular displacement
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D
Coefficient of thermal conductivity
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Solution
The correct option is
D
Coefficient of thermal conductivity
W
a
t
t
(
m
e
t
e
r
)
×
(
k
e
l
v
i
n
)
=
M
L
2
T
−
3
L
K
=
M
L
T
−
3
K
−
1
Coefficient of thermal conductivity
(
k
)
=
(
q
A
)
×
t
d
T
(
q
/
A
)
=
heat transfer per unit area
(
W
/
m
2
)
d
T
=
temperature difference
t
=
thickness
[
k
]
=
[
M
L
2
T
−
3
]
[
L
−
2
]
[
L
]
[
K
]
=
M
L
T
−
3
K
−
1
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