Wavelength of light used in an optical instrument are -1 - 4000 A- then ratio of their respective resolving power corresponding to -1 and -2 is

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Wavelength of light used in an optical instrument are $λ_{1} = 4000 A^{\circ}$ then ratio of their respective resolving power (corresponding to $λ_{1} a n d λ_{2}$ ) is

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λ_{1} = 4000 ˚ A

λ_{2} = 5000 ˚ A

λ_{1}

λ_{2}

λ_{1} = 4000 o A

λ_{2} = 5000 o A

λ_{1}

λ_{2}

Wavelength of light used in an optical instrument are $λ_{1} = 4000 ˙ A$ and $λ_{2} = 5000 ˙ A$ then ratio of their respective resolving power is

λ_{1} = 4000 Å

λ_{2} = 6000 Å

λ_{1} = 4000 ˚ A

λ_{2} = 6000 ˚ A

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