Wavelength of photon having energy 2.5eV: (Take Planck's constant,h=6.6×10−34Js)
A
6.20×10−3oA
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B
6.20×103oA
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C
4.95×103oA
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D
4.95×10−3oA
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Solution
The correct option is C4.95×103oA We know that, 1eV=1.6×10−19J
Again, Energy (E)=hcλ
Where, λ=Wavelength c=Velocity of light ∴λ=hcE=6.6×10−34×3×1082.5×1.6×10−19=4.95×103oA