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Question

# Wavelength of two notes in air are (90175)m and (90173)m, respectively. Each of these notes produces 4 beats per second with a third note of a fixed frequency. Calculate the velocity of sound in air in m/s.

A
320
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B
360
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C
420
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D
460
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Solution

## The correct option is B 360Given λ1=90175m and λ1=90173m If f1 and f2 are the corresponding frequencies and v is the velocity of sound in air, we have v=f1λ1 and v=f2λ2 f1=vλ1 and f2=vλ2 Since, λ1<λ2 we must have f1>f2 If f is the frequency of the third note, then f1−f=4 and f−f2=4 ⇒f1−f2=8 or vλ1−vλ2=8 v[1759−17390]=8 v = 360m/s

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