Wavelength of two notes is air 80195 m and 80193 m. Each note produces 5 beats per second with a third note of a fixed frequency. The speed of sound in air is:
A
300ms−1
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B
340ms−1
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C
375ms−1
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D
400ms−1
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Solution
The correct option is D400ms−1 f1−f0=5 fa−f2=5 ⇒f1−f2=10 c(80195)−c(80193)=10 ⇒2c80=10 ⇒C=400ms−1.