We apply a force of $10 N$ on a cord wrapped around a cylinder of mass $2 k g$ . The cylinder rolls without slipping on the floor. What is its kinetic energy (in joule) when cylinder has moved by a distance of $3 / 5 m$ ?

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Solution

Since $10 < m g$ , the cylinder rolls on the ground without lifting up. Therefore,
$K E =$ workdone $= F \times$ displacement
$= 10 \times \frac{3}{5} = 6 J$

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We apply a force of 10 N on a cord wrapped around a cylinder of mass 2 kg. The cylinder rolls without slipping on the floor. What is its kinetic energy (in joule) when cylinder has moved by a distance of 3/5 m?

Since 10<mg, the cylinder rolls on the ground without lifting up. Therefore,KE= workdone =F× displacement=10×35=6 J

We apply a force of $10 N$ on a cord wrapped around a cylinder of mass $2 k g$ . The cylinder rolls without slipping on the floor. What is its kinetic energy (in joule) when cylinder has moved by a distance of $3 / 5 m$ ?

Since $10 < m g$ , the cylinder rolls on the ground without lifting up. Therefore,
$K E =$ workdone $= F \times$ displacement
$= 10 \times \frac{3}{5} = 6 J$