We are given y = ln(x+1). Find x in terms of y
ey - 1
ey + 1
ey
None of these.
y = ln (x+1)
Here, we have to express x as a function of y.
We know this property of logarithm -
If logb a = c
then a = bc
So, ey = x +1
Or x = ey - 1
Find the integral of the given function w.r.t - x
y=x−1x+1x2