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Question

We can express 7103 as 7×(501)51=7[50k1]


A

True

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B

False

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Solution

The correct option is A

True


7103 = 7 ×(49)51

= 7 ×(501)51

7 ×(501)51 = 7[51C0(50)5151C1(50)50+51C2(50)49............51C50(50)151C51]

7 ×(501)51 = 7[51C0(50)5151C1(50)50+51C2(50)49............51C50(50)11]

51C0(50)5151C1(50)50+51C2(50)49............51C50(50)1 is a multiple of 50.We will replace it with 50k

7 ×(501)51=7[50k1]


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