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Standard X

Chemistry

Mole Concept

We define p v...

Question

We define p value of a term (say $x$ ) as $p_{x} = - l o g x$ .
Molar concentration of ${A g}^{+}$ in a solution that has $p_{A g}$ = 6.6990 is $x \times 10^{- 7}$ . Here, $x$ (nearest integer) is :

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Solution

$p_{A g^{+}} = - l o g [A g^{+}] = 6.6990$

Hence, $[A g^{+}] = 10^{- 6.6990} = 2 \times 10^{- 7}$

Hence $x = 2$

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We define p value of a term (say x) as px=−log x.Molar concentration of Ag+ in a solution that has pAg = 6.6990 is x×10−7. Here, x (nearest integer) is :

pAg+=−log[Ag+]=6.6990Hence, [Ag+]=10−6.6990=2×10−7Hence x=2

We define p value of a term (say $x$ ) as $p_{x} = - l o g x$ .
Molar concentration of ${A g}^{+}$ in a solution that has $p_{A g}$ = 6.6990 is $x \times 10^{- 7}$ . Here, $x$ (nearest integer) is :

$p_{A g^{+}} = - l o g [A g^{+}] = 6.6990$

Hence, $[A g^{+}] = 10^{- 6.6990} = 2 \times 10^{- 7}$

Hence $x = 2$