We draw a triangle with length of sides 5cm,8cm and 11cm and draw a parallelogram equal in area to that triangle and having an angle 60∘. [Let us write instruction process and proof]
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Solution
Steps of Construction:
1. We draw a triangle ABC of given dimensions.
2. We draw a perpendicular bisector of side AB which intersects AB at D.
3. Join C to D.
4. Draw a line parallel to AB through C by completing the parallelogram ACQB.
5. From D, construct ∠GDB=60∘.
6. The line cuts parallel line through C at E.
7. From E, cut an arc of length DB on the parallel line.
8. Mark the point as F.
9. Join F to B.
10. DBFE is the required parallelogram.