Question

We have $1.6gC{H}_4$ , $1.7gN{H}_3$ and $1.8g{H}_{2}O$.
Select correct alternate(s).

• A. There are equal number of moles of each reactant.
• B. Total number of atoms in $C{H}_4>N{H}_3>H_{2}O$.
• C. Total number of H-atoms are in the ratio of $4:3:2$.
• D. Total number of C atoms in $C{H}_4<$ that of N atoms in $N{H}_3<$ that of O atoms inn $H_{2}O$.

Answer 1

Answer: (A), (B), (C)

The correct options are
A There are equal number of moles of each reactant.
B Total number of atoms in $C{H}_4>N{H}_3>H_{2}O$.
C Total number of H-atoms are in the ratio of $4:3:2$.

Species	Amount		Mole	Total atoms	H-atoms
$C{H}_4$	1.6 g		0.1	0.5 $N_0$	0.4 $N_0$
$N{H}_3$	1.7 g		0.1	0.4 $N_0$	0.3 $N_0$
$H_{2}O$	1.8 g		0.1	0.3 $N_0$	0.2 $N_0$

They have equal number of moles.
Number of atoms is $C{H}_4>N{H}_3>H_{2}O$
Ratio of H-atom is $4:3:2$.