Question

We have 2 ohm resistors. Sort the combinations in increasing order of their combined resistances.

• A. 5 in series
• B. 4 in parallel
• C. 8 in parallel
• D. 10 in parallel
• E. 4 in series

Answer 1

For series combination
$R_{eq}=R_1+R_2+...+R_n$
For parallel combination of resistors
$\frac{1}{R_{eq}}=\frac{1}{R_1}+\frac{1}{R_2}+...+\frac{1}{R_n}$ .
Therefore, 5 resistors of 2$\Omega$ in series will have $R_{eq}=10\Omega$
4 resistors of 2$\Omega$ in series will have $R_{eq}=8\Omega$
8 resistors of 2$\Omega$ in parallel will have $R_{eq}=0.25\Omega$
4 resistors of 2$\Omega$ in parallel will have $R_{eq}=0.5\Omega$
10 resistors of 2$\Omega$ in parallel will have $R_{eq}=0.20\Omega$