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Question

We have 2 ohm resistors. Sort the combinations in increasing order of their combined resistances.

A
5 in series
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B
4 in series
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C
4 in parallel
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D
8 in parallel
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E
10 in parallel
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Solution

For series combination
Req=R1+R2+...+Rn
For parallel combination of resistors
1Req=1R1+1R2+...+1Rn .
Therefore, 5 resistors of 2Ω in series will have Req=10Ω
4 resistors of 2Ω in series will have Req=8Ω
8 resistors of 2Ω in parallel will have Req=0.25Ω
4 resistors of 2Ω in parallel will have Req=0.5Ω
10 resistors of 2Ω in parallel will have Req=0.20Ω

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