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Standard XII

Physics

Velocity of COM

We have 3 con...

Question

We have 3 conducting spheres A,B and C of radius 2R, R and $\frac{R}{2}$ respectively. Out of the 3, A is charged to some charge. Charged sphere A touches B and then both are separated by distance d. Force between A and B is F. Again this sphere B touches C and is separated by distance d from C then force between B and C is

\frac{F}{9}

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\frac{F}{8}

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\frac{F}{6}

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\frac{F}{2}

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Solution

The correct option is A $\frac{F}{9}$

$F = K \frac{\frac{2 Q}{3} . \frac{Q}{3}}{d^{2}}$

$F^{'} = K \frac{\frac{2 Q}{9} \times \frac{Q}{9}}{d^{2}}$

$F^{'} = \frac{F}{9}$

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The correct option is A F9 F=K2Q3.Q3d2 F′=K2Q9×Q9d2 F′=F9

The correct option is A $\frac{F}{9}$

$F = K \frac{\frac{2 Q}{3} . \frac{Q}{3}}{d^{2}}$

$F^{'} = K \frac{\frac{2 Q}{9} \times \frac{Q}{9}}{d^{2}}$

$F^{'} = \frac{F}{9}$