We have a car lot having $15$ Toyotas and $17$ Hondas. There is a second car lot having $13$ Toyotas and $12$ Hondas. A car is driven out from either of the $2$ lots. The probability that it is a Toyota is $\frac{1}{2}$ - $\frac{k}{1600}$ . Find the value of $k$ .

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Solution

Using the tree shown in the figure
$P (t o y o t a) = \frac{1}{2} \frac{15}{32} + \frac{1}{2} \frac{13}{25}$
$= \frac{791}{1600} = \frac{1}{2} - \frac{9}{1600}$ $= \frac{1}{2}$ $- \frac{k}{1600}$
$∴ k = 9$

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We have a car lot having 15 Toyotas and 17 Hondas. There is a second car lot having 13 Toyotas and 12 Hondas. A car is driven out from either of the 2 lots. The probability that it is a Toyota is 12-k1600. Find the value of k.

Using the tree shown in the figureP(toyota)=121532+121325=7911600=12−91600 =12 −k1600∴k=9

We have a car lot having $15$ Toyotas and $17$ Hondas. There is a second car lot having $13$ Toyotas and $12$ Hondas. A car is driven out from either of the $2$ lots. The probability that it is a Toyota is $\frac{1}{2}$ - $\frac{k}{1600}$ . Find the value of $k$ .

Using the tree shown in the figure
$P (t o y o t a) = \frac{1}{2} \frac{15}{32} + \frac{1}{2} \frac{13}{25}$
$= \frac{791}{1600} = \frac{1}{2} - \frac{9}{1600}$ $= \frac{1}{2}$ $- \frac{k}{1600}$
$∴ k = 9$