Question

We have a faulty barometer. When faulty barometer reads 69 cm of Hg, true barometer reads 73 cm of Hg, true barometer reads 75 cm of Hg. When the reading of faulty barometer is 65 cm, reading of true barometer will be

Answer 1

We have a faulty barometer reads $69cm$ of $HG$, true barometer reads $=73cm$ of $HG$, true barometer reads $=75cm$ of $Hg$

The faulty barometer reads $73cm$ of $Hg$ whereas actual pressure is the faulty barometer reads $75cm$ of $Hg$.

$P_{act}=75$ cm of Hg

So, $P_{ac}-P_a=P_{finally}$

$(75-73)=2$

$69,73$ $72.6$ $75.6$

$75?$ $72.0$ $2$

$\frac{73\times 75}{69}=79.34$