Question

We have a galvanometer of resistance 25$\Omega$. It is shunted by a 2.5$\Omega$ wire, the part of total current that flows through the galvanometer is given as:

• A. $\frac{i}{i_0}=\frac{3}{11}$
• B. $\frac{i}{i_0}=\frac{4}{11}$
• C. $\frac{i}{i_0}=\frac{2}{11}$
• D. $\frac{i}{i_0}=\frac{1}{11}$

Answer 1

The correct option is D $\frac{i}{i_0}=\frac{1}{11}$

$G=25\Omega ,S=2.5\Omega$
We have, $i_g=i_0\frac{S}{G+S}=i_0\frac{2.5}{(25+2.5)}$
$=i_0\frac{2.5}{27.5}=i_0\frac{1}{1I}$
$\therefore \frac{i}{i_0}=\frac{1}{11}$
where I $\to$ current through galvanometer $I_0\to$ Total current.