We have an electric kettle rated at (60V, 5A). What is the electrical energy dissipated by the kettle in 5 minutes of continuous operation?

100 m/s

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50 m/s

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60√20 m/s

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30√20 m/s

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Solution

The correct option is D
30√20 m/s

$H = V I t = 60 V \times 5 A \times 300 s = 90000 J = 90 k J$

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We have an electric kettle rated at (60V, 5A). What is the electrical energy dissipated by the kettle in 5 minutes of continuous operation?

The correct option is D 30√20 m/s H=VIt=60V×5A×300s=90000 J=90 kJ

The correct option is D
30√20 m/s

$H = V I t = 60 V \times 5 A \times 300 s = 90000 J = 90 k J$