Question

We have an isosceles triangle ABC with $m\angle B=m\angle C={65}^{\circ }$ . The measure of angle A is degree.

Answer 1

Triangle ABC is isosceles with $m\angle B=m\angle C={65}^{\circ }$.
$\because m\angle A+m\angle B+m\angle C={180}^{\circ }$
$m\angle A={180}^{\circ }-(m\angle B+m\angle C)={180}^{\circ }-({65}^{\circ }+{65}^{\circ })={180}^{\circ }-{130}^{\circ }m\angle A={50}^{\circ }$