Question

We know that current $I=neA{V}_d$ where $V_d$ is the drift speed, A is the cross sectional area, e is the magnitude of charge on an electron and n is the number of free charge carriers in unit volume of a conductor. In a conductor of non-uniform cross-sectional area as shown

1: The current at P will be more than the current at Q
2: Because current is directly proportional to cross-sectional area so current increases as the cross sectional area increases

• A. Statement 1 is correct, Statement 2 is the correct and Statement 2 is the correct explanation for statement 1
• B. Statement 1 is correct, Statement 2 is the correct and Statement 2 is not the correct explanation of statement 1
• C. Statement 1 is correct but Statement 2 is wrong
• D. Both statements are wrong

Answer 1

The correct option is D Both statements are wrong

For a non-uniform cross-section the value of $A{V}_d$ remains constant (where A is the cross sectional area and $V_d$ is the drift speed. So when the area increases, the $V_d$ decreases simultaneously. The current flowing remains constant.
It has to be, otherwise say current increases at P, it would be against the law of conservation of charge (where would extra current come from?)