wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

We know that If a ball of mass 1 kg is kept at a height 10 m possess potential energy mgh i.e. (1×10×10)=100 J. (Taking Earth surface as reference, where m = mass of object, g = acceleration due to gravity, h = height of object from earth surface.)

what will be the kinetic energy of the ball falling freely from a height of 10 m when it reaches the ground? (take g = 10 m/s2 and neglect air drag)

A
100 J
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
50 J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
10 J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0 J
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 100 J
Initially, the ball has potential energy which is later converted to kinetic energy.

Potential energy = 1×10×10=100 J (at h = 10m)
When the ball reaches the bottom, i.e., h = 0, potential energy will become 1×10×0=0 J.

So in absence of air drag, all potential energy will be converted to kinetic energy.

Therefore, kinetic energy when the ball hits the ground will be 100 J.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Energy
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon