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Question
We know that If a ball of mass 1 kg is kept at a height 10 m possess potential energy “mgh” i.e. (1×10×10)=100 J. (Taking earth surface as reference, where m = mass of object, g = acceleration due to gravity, h = height of object from earth surface.) what will be the kinetic energy of the ball when the ball is allowed to freely fall from a height 10m from the surface of earth and it hits the ground? (take g = 10 m/s2 and neglect air drag)
We know that If a ball of mass 1 kg is kept at a height 10 m possess potential energy “mgh” i.e. (1×10×10)=100 J. (Taking earth surface as reference, where m = mass of object, g = acceleration due to gravity, h = height of object from earth surface.) what will be the kinetic energy of the ball when the ball is allowed to freely fall from a height 10m from the surface of earth and it hits the ground? (take g = 10 m/s2 and neglect air drag)
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Solution
The correct option is A 100 J
Initially, the ball has potential energy which is later converted to kinetic energy.
Potential energy = 1×10×10=100 J (at h = 10m)
When the ball reaches the bottom, i.e., h = 0, potential energy will become 1×10×0=0 J.
So in absence of air drag, all potential energy will be converted to kinetic energy.
Therefore, kinetic energy when the ball hits the ground will be 100 J.
Initially, the ball has potential energy which is later converted to kinetic energy.
Potential energy = 1×10×10=100 J (at h = 10m)
When the ball reaches the bottom, i.e., h = 0, potential energy will become 1×10×0=0 J.
So in absence of air drag, all potential energy will be converted to kinetic energy.
Therefore, kinetic energy when the ball hits the ground will be 100 J.
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