We wish to seen inside an atom. Assuming the atom to have a diameter of $100 p m$ ,this means that one must be able to resolve a width of say $10 p m$ . If an electron microscope is used, the minimum electron energy required is about:

1.5 k e V

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15 k e V

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150 k e V

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1.5 M e V

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Solution

The correct option is B $15 k e V$
The resolution required is 10 pm, So if the wavelength of an electron is equal to 10 pm then we can see the whole atom.
Using De-Broglie hypothesis $λ = h / p$ . Where $λ =$ wavelength of electron, h= Planck's constant, p = momentum of electron.
Here we have given $λ = 10 p m$ , by solving above equeation, we got $p = 6.26 \times 10^{- 23} m k g / s$ .
we know $p = m v$ ; K.E = $m v^{2}$ ,
So K.E = $p^{2} / 2 m$
so K.E = $15.04 \times 10^{3}$ ev

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We wish to seen inside an atom. Assuming the atom to have a diameter of 100 pm,this means that one must be able to resolve a width of say 10 pm. If an electron microscope is used, the minimum electron energy required is about:

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