Weight of $40$ eggs were recorded as given below
Weight in grams $85 - 90$ $90 - 95$ $95 - 100$ $100 - 105$ $105 - 110$
Number of eggs $4$ $12$ $14$ $8$ $2$
Find the modal weight.

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Solution

In the given frequency distribution, $h = 5$

Class $95 - 100$ has maximum frequency i.e, $14$

Therefore, $95 - 100$ is the model class in which $l = 95$ and $f_{1} = 14$

Here, $f_{0} = 12$ and $f_{2} = 8$

Mode $= l + (\frac{f_{1} - f_{0}}{2 f_{1} - f_{0} - f_{2}}) \times h$

$= 95 + (\frac{14 - 12}{28 - 12 - 8}) \times 5$

$= 95 + \frac{10}{8}$

$= 95 + 1.25$

$= 96.25$

The model weight is equal to $96.25$ grams.

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Weight in grams	$85 - 90$	$90 - 95$	$95 - 100$	$100 - 105$	$105 - 110$
Number of eggs	$4$	$12$	$14$	$8$	$2$

Weight of 40 eggs were recorded as given belowWeight in grams85−9090−9595−100100−105105−110Number of eggs4121482Find the modal weight.

In the given frequency distribution, h=5Class 95−100 has maximum frequency i.e, 14Therefore, 95−100 is the model class in which l=95 and f1=14Here, f0=12 and f2=8Mode =l+(f1−f02f1−f0−f2)×h=95+(14−1228−12−8)×5=95+108=95+1.25=96.25The model weight is equal to 96.25 grams.

Weight of $40$ eggs were recorded as given below
Weight in grams $85 - 90$ $90 - 95$ $95 - 100$ $100 - 105$ $105 - 110$
Number of eggs $4$ $12$ $14$ $8$ $2$
Find the modal weight.