Weight of a body of mass m decreases by 1% when it is raised to height h above the earth’s surface. If the body is taken to a depth h in a mine, change in its weight is
0.5% decrease
Percentage change in g when the body is raised to height h, Δgg×100%=2h×100R=1%
Percentage change in g when the body is taken to a depth d,
Δgg×100%=dR×100%=hR×100%[As d=h]
∴ Percentage decreases in weight =12(2hR×100)=12(1%)=0.5%