Weight of $S O_{2}$ that can be made by burning sulphur in 5.0 moles of oxygen is .

640 grams

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160 grams

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80 grams

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320 grams

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Solution

The correct option is D 320 grams
$S + O_{2} \to S O_{2}$
From the above balanced equation we see that,
1 mole of sulphur reacts with 1 mole of $O_{2}$ to form 1 mole of $S O_{2}$ .
So,
Mass of $S O_{2}$ formed from 5 mole = $5 \times 64 = 320 g$

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