Question

What amount of bromine will be required to convert $2\mathrm{gm}$ of Phenol Into $2,4,6-\mathrm{Tribromophenol}$?

• A. $4.00$
• B. $2.00$
• C. $10.22$
• D. $6.00$

Answer 1

The correct option is C

$10.22$

Explanation for correct option:

(c )$10.22$

Step 1: Equation

Step 2: writing the equation with atomic units required for each substance:

$$\begin{gathered} \mathrm{Phenol}+3{\mathrm{Br}}_2\to 2,4,6-\mathrm{tribromophenol}+3\mathrm{HBr} \\ 94\mathrm{u}480\mathrm{u}331\mathrm{u}243\mathrm{u} \end{gathered}$$

Step 3: calculating quantity of bromine if $2\mathrm{gm}$ of phenol is used:

$$\begin{gathered} \mathrm{Phenol}+3{\mathrm{Br}}_2\to 2,4,6-\mathrm{tribromophenol}+3\mathrm{HBr} \\ 2\mathrm{g}\mathbf{x}\mathrm{g} \end{gathered}$$

• $$\begin{gathered} 94\mathrm{g}\mathrm{of}\mathrm{phenol}\mathrm{requires}=480\mathrm{g}\mathrm{of}{\mathrm{Br}}_2 \\ \mathrm{Therefore},2\mathrm{g}\mathrm{of}\mathrm{phenol}\mathrm{requires}=\left(\frac{480}{94}\right)\times 2=10.22\mathrm{g}. \end{gathered}$$
• To convert $2\mathrm{gm}$ phenol into$2,4,6-\mathrm{Tribromophenol}$, $10.22\mathrm{grams}$ bromine will be required
• Therefore the correct option is (c ) $10.22$

The explanation for incorrect options:

$10.22\mathrm{grams}$ of bromine will be required. Hence, options (A),(B), and (D) are incorrect.

Therefore the correct option is (c ) $10.22$.