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Osmotic Pressure

What amount o...

Question

What amount of $C a {C l}_{2}$ ( $i = 2.47$ ) is dissolved in $2$ litres of water so that its osmotic pressure is $0.5 a t m$ at $27^{o} C$ ?

3.42 g

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9.24 g

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2.834 g

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1.820 g

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Solution

The correct option is D $1.820 g$
$Π = i \times C R T$

$0.5 = 2.47 \times \frac{W}{110.98 \times 2} \times 300 \times 0.0821$

$W = \frac{0.5 \times 110.98 \times 2}{2.47 \times 300 \times 0.0821}$

$W = 1.820 g$

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Similar questions

Determine the amount of CaCl2 (i = 2.47) dissolved in 2.5 litre of water such that its osmotic pressure is 0.75 atm at 27°C.

C a C l_{2}

i = 2.47

2.5 L

300 K

0.75

C a C l_{2}

111 g . m o l^{- 1}

R = 0.082 L . a t m . K^{- 1} m o l^{- 1}

QUESTION 2.40

Determine the amount of $C a C l_{2}$ (i = 2.47) dissolved in 2.5 L of water such that its osmotic pressure is 0.75 atm at $27^{\circ} C$ .

C a C l_{2}

27^{0} C

C a C l_{2}

C a C l_{2} (i = 2.4)

2.5 l

0.75 atm

27^{\circ} C

R = \frac{1}{12} latm/molK

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