Question

What amount of oxygen contains $1.8\times {10}^{22}$ dioxygen molecules?

• A. 9.6 g
• B. 0.096 g
• C. 96.0 g
• D. 0.960 g

Answer 1

The correct option is D 0.960 g

We have,

$6.0\times {10}^{23}$ molecules contain 32g of oxygen molecules.

Therefore, $1.8\times {10}^{22}$ molecules contain oxygen $=\frac{32}{6.0\times {10}^{23}}\times (1.8\times {10}^{22})=0.960g$