What amount of $P b (N O_{3})_{2}$ , when added to water to make $1$ liter of solution, to produce a solution with a molarity of $1.0 M$ ?

144 g r a m s

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331 g r a m s

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317 g r a m s

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0.003 g r a m s

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0.5 m o l e s

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Solution

The correct option is B $331 g r a m s$
Molecular weight of $P b (N O_{3})_{2}$ $=$ $331 g r a m s$
Molarity $=$ weight(gram)/(molecular weightvolume)
or $1$ $=$ $w e i g h t (g r a m) / (1 331)$
so $w e i g h t$ $=$ $331 g r a m s$

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