What are the atomic no. and symbol of elements whose outermost electrons are represented as - $3 d^{6}, 4 s^{2}$ ?

_{26} Fe

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_{24} Cr

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_{44} Ru

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_{25} Fe

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Solution

The correct option is A $_{26} Fe$
The element with the valence shell configuration of $3 d^{6} 4 s^{2}$ is iron. Its atomic number is $2 + 8 + 8 + 6 + 2 = 26$ . Its symbol is $^{26} F e .$

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