What are the conjugate acid-base pairs in the following reaction ?
$H_{3} P O_{4 (a q)} + H_{2} O_{(l)} \to H_{2} P O_{4 (a q)}^{-} + H_{3} O_{(a q)}^{+}$

H_{3} P O_{4 (a q)} / H_{2} O_{(l)}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

H_{3} P O_{4 (a q)} / H_{2} P O_{4 (a q)}^{-}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

H_{2} O_{l)} / H_{2} P O_{4 (a q)}^{-}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

H_{2} O_{(l)} / H_{2} O_{(l)}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $H_{3} P O_{4 (a q)} / H_{2} P O_{4 (a q)}^{-}$
$H_{3} P O_{4} (a q) + H_{2} O (l) ⟶ H_{2} P O_{4}^{-} (a q) + H_{3} O^{+} (a q)$
A conjugate acid- base pair is such that the species constituting the pair differ in one proton $(H^{+})$ .
In the above reaction, acid $H_{3} P O_{4}$ loses a proton to give its conjugate base $H_{2} P O_{4}^{-}$ .
Hence, the conjugate acid- base pair in this reaction is $H_{3} P O_{4} (a q) / H_{2} P O_{4}^{-} (a q)$

Suggest Corrections

Similar questions

P_{4} O_{10} (s) + H_{2} O (l) ⟶ H_{3} P O_{4} (a q)

H_{2} O

H_{2} O (l) b a s e + H_{2} O (x) (l) ⇋ H_{3} O^{+} (a q .) + O H^{-} (y) (a q .)

H_{2} S O_{4} (a q) + H_{2} O (l) ⇌ H_{3} O^{+} (a q) + H S O_{4}^{-} (a q)

H C_{2} H_{3} O_{2} (a q) + H_{2} O (l) ⇌ H_{3} O^{+} (a q) + C_{2} H_{3} O_{2}^{-} (a q)

H_{2} S_{(g)} + {H_{2} O}_{(l)} ⇌ {H_{3} O}_{(a q)}^{+} + {H S^{-}}_{(a q)}

N a N H_{2 (s)} + H_{2} O_{(l)} ⇌ N a_{(a q)}^{+} + O H_{(a q)}^{-} + N H_{3 (a q)}

Join BYJU'S Learning Program