What are the constituent amines formed when the mixture of (i) and (ii) undergoes Hoffmann bromamide degradation?
$P h (o - D) C O N H_{2} (i) P h C O 15 N H_{2} (i i)$

P h (o - D) N H_{2}

P h (o - D) 15 N H_{2}

P h N H_{2}

P h 15 N H_{2}

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P h (o - D) N H_{2}

P h 15 N H_{2}

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P h (o - D) 15 N H_{2}

P h 15 N H_{2}

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P h 15 N H D

P h N H_{2}

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Solution

The correct option is B $P h (o - D) N H_{2}$ $P h 15 N H_{2}$
Solution:- (B)
Since the reaction is intramolecular, no cross product will be formed.
$P h (o - D) C O N H_{2} {B r}_{2} - -- \to K O H p H (o - D) N H_{2}$
$P h - C O N H_{2} ⟶ P h - N H_{2}$

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