What are the coordinates of the center of the circle,
${(x + 3)}^{2} + {(y - 5)}^{2} = 16$ ?

(3, 5)

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(- 3, 5)

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(- 3, - 5)

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(3, - 5)

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Solution

The correct option is B $(- 3, 5)$
the general equation of a circle with center at (a,b) and radius r is
$(x - a)^{2} + (y - b)^{2} = r^{2}$
$(x - 3)^{2} + (y - 5)^{2} = 16$
comparing the above two equations we get
the center of the circle is $(- 3, 5)$ and radius is $\sqrt{16} = 4$

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