What are the coordinates of the centre of the circle $x^{2} + y^{2} - 2 x - 2 y + 1 = 0$ .

(-1, -1)

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(0, 0)

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(-1, 1)

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(1, 1)

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Solution

The correct option is D
(1, 1)

Given circle is,

$x^{2} + y^{2} - 2 x - 2 y + 1 = 0$

$(x - 1)^{2} - 1 + (y - 1)^{2} - 1 + 1 = 0$

i.e., $(x - 1)^{2} + (y - 1)^{2} = 1$

$∴$ Centre $\equiv$ (1, 1)

Radius = 1

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90 °

x^{2} + y^{2} = 1, x^{2} + y^{2} - 2 x - 3 = 0

x^{2} + y^{2} - 2 y - 3 = 0

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