Question

What are the different oxidation states of Bromine in the compound $B{r}_3{O}_8$?

• A. All bromine atoms are present in $+\frac{8}{3}$ oxidation state
• B. $2$ Bromine atoms in $+6$ state and one in $+4$ state
• C. $2$ Bromine atoms in $+4$ state and one in $+6$ state
• D. $2$ Bromine atoms in $+8$ state and one in $+4$ state

Answer 1

The correct option is B $2$ Bromine atoms in $+6$ state and one in $+4$ state


There are two different types of bromine atoms:
1. That has 3 oxygen atoms attached to it (Two terminal bromines)
2. That has 2 oxygen atoms attached to it. (Bromine atom in middle)
Let oxidation state of Bromine atom that is attached to 3 oxygen atoms be $x$.
Thus:
$x+(3\times -2)=0x=+6$
Both the terminal Bromine atoms have $+6$ oxidation state.

Let oxidation state of Bromine atom which is attached to 2 oxygen atoms is $y$ :
Then,
$y+(2\times (-2\left)\right)=0y=+4$
So option b is correct.