What are the electronic configuration of Na+ and Cl− ions?
A
Na+=2,8,2 and Cl−=2,8,7
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B
Na+=2,8 and Cl−=2,8,8
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C
Na+=2,8,2 and Cl−=2,8,6
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D
Na+=2,8 and Cl−=2,8,7
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Solution
The correct option is BNa+=2,8 and Cl−=2,8,8 Atomic number of Na=11 and thus atomic no. of Na+=10 and E.C =2,8 Atomic number of Cl = 17 and thus atomic no. of Cl−= 18 and E.C = 2, 8, 8