What are the factors of $(101^{2} - 99^{2})$ ?

101

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Solution

The correct options are
B
99

C
2

Using the algebraic Identity $(a^{2} - b^{2}) = (a - b) (a + b)$

$(a - b)$ and $(a + b)$ are factors of $a^{2} - b^{2}$ .

Putting $a = 101$ and $b = 99$ , we find that $2$ and $200$ both are the factors of $(101^{2} - 99^{2})$ .

Suggest Corrections

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