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Byju's Answer
Standard V
Mathematics
Finding HCF Using Common Factors
What are the ...
Question
What are the factors of the HCF of 48 and 64?
A
2, 4, and 6
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B
2, 4, 8, 12, and 16
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C
1, 2, 4, 6, 8, and 16
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D
1, 2, 4, 8, and 16
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Solution
The correct option is
D
1, 2, 4, 8, and 16
HCF of 48 and 64:
2
48
,
64
2
24
,
32
2
12
,
16
2
6
,
8
3
,
4
There are no common factors between 3 and 4.
So, HCF = 2 × 2 × 2 × 2
= 16
Factors of 16: 1, 2, 4, 8, and 16
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