Question

What are the factors of the terms of the given expression: $\frac{6x}{y}-(x+1)\left(y\right)$?

• A. $6,x,\frac{1}{y}and(x+1),y$ for first and second part respectively
• B. $6,x,\frac{1}{y}and-1,(x+1),y$ for first and second part respectively
• C. $6,\frac{x}{y}and-(x+1)$ for first and second part respectively
• D. $6,x,\frac{1}{y}andx,1,y$ for first and second part respectively

Answer 1

The correct option is B

$6,x,\frac{1}{y}and-1,(x+1),y$ for first and second part respectively

The first term of the given expression is $\frac{6x}{y}$. Factors are $6,x,\frac{1}{y}$.

Similarly, second term of the expression is $-(x+1)\left(y\right)$. Since the negative term is associated with the it, factors are $-1$, $(x+1)andy$.