Question

What are the intercepts of $5x+3y=-7$ ?

Answer 1

Find the intercepts of $5x+3y=-7$.

Equation of $x$-axis is $y=0$.

So after putting the value of $y=0$ in the equation, l get an intercept from the $x$-axis:

$\begin{array}{rcl}5\left(x\right)+3\left(0\right)& =& -7\\ & \Rightarrow & x=-\frac{7}{5}\end{array}$.

Therefore, the equation of the $y-$axis is $x=0$.

Now, putting $x=0$ in the given equation we will get an intercept from the $y-$axis:

$\begin{array}{rcl}5\times 0+3\times y& =& -7\\ & \Rightarrow & y=-\frac{7}{3}\end{array}$

Hence, the intercepts of the given equiation are $-\frac{7}{5}\mathrm{and}-\frac{7}{3}$.