What are the missing products of the following reaction? ${N H}_{4} C l + {C a (O H)}_{2} \to___+ C a {C l}_{2}$

N_{2}

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{N H}_{3}

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H_{2} O

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{N H}_{3} + N_{2}

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{N H}_{3} + H_{2} O

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Solution

The correct option is E ${N H}_{3} + H_{2} O$
Calcium hydroxide reacts with ammonium chloride to give ammonia, water and calcuim chloride.

${2 N H}_{4} C l + C a {(O H)}_{2} \to {2 N H}_{3} + {2 H}_{2} O + {C a C l}_{2}$

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Similar questions

N H_{4} C l + C a (O H)_{2} \to C a C l_{2} + N H_{3} + H_{2} O

Balance the following equation b hit and trial method :. NH4Cl + Ca(OH)2 ------------> CaCl2 + H2O + NH3

M n O_{2} + H C l \to M n C l_{2} + C l_{2} + H_{2} O

N H_{4} C l + C a (O H)_{2} \to N H_{3} + C a C l_{2} + H_{2} O

B a C l_{2} + A l_{2} (S O_{4})_{3} \to B a S O_{4} + A l C l_{3}

N a A l O_{2} + H_{2} O + C O_{2} \to A l H_{3} + N a_{2} C O_{3}

N H_{3} + O_{2} \to N O + H_{2} O

Z n + H N O_{3} \to Z n (N O_{3})_{2} + N O_{2} + H_{2} O

H_{2} S + O_{2} \to H_{2} O + S O_{2}

P b O + C \to P b + C O_{2}

B a C l_{2} + H_{2} S O_{4} \to B a S O_{4} + H C l

C H_{4} + O_{2} \to C O_{2} + H_{2} O

C u O + N H_{3} \to N_{2} + H_{2} O + C u

C u O + N H_{3} ⟶ C u + H_{2} O + N_{2}

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