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Question

What are the possible expressions for the dimensions of the cuboid whose volumes are given below?
(i) Volume: 3x212x

(ii) Volume: 12ky2+8ky20k

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Solution

(i)Volume: 3x212x

We know that Volume of Cuboid = length × breadth × height

Volume of cuboid = 3x212x

We need to factorize this given polynomial to find values of length, breadth and height.

3x212x

=3x(x−4)

Therefore, one possibility is that length =3, breadth =x and height =(x−4)

(ii)Volume: 12ky2+8ky20k

We know that Volume of Cuboid = length × breadth × height

Volume of cuboid =12ky2+8ky20k

We need to factorize this given polynomial to find values of length, breadth and height.

12ky2+8ky20k

=12ky2+20ky12ky20k

=4ky(3y+5)−4k(3y+5)

=(3y+5)(4ky−4k)

=(3y+5)4k(y−1)=4k(y−1)(3y+5)

Therefore, one possibility is that length =4k, breadth =(y−1) and height =(3y+5)


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