What are the products when ethyl isopropyl ether is cleaved with concentrated $H I$ ?

Ethanol and 2-iodo-2-methyl propane

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Ethanol and 2-methyl propane

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Iodoethane and isopropyl alcohol

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Iodoethane and 2-methyl propane

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Solution

The correct option is C Iodoethane and isopropyl alcohol
The reaction of ethyl isopropyl ether with concentrated hydroiodic acid gives iodoethane and isopropyl alcohol.

In this reaction, lower alkyl halide and higher alcohol are obtained.

Option C is correct.

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