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Oxides of Nitrogen

What are the ...

Question

What are the products when we dissolve $N a C l$ in $H_{2} O$ ?

A

N a^{+}

and

C l^{-}

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B

N a^{+} (a q .)

and

C l^{-} (a q .)

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C

N a^{+}

,

C l^{-}

,

H^{+}

and

O H^{-}

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D

none of these

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Solution

The correct option is B $N a^{+} (a q .)$ and $C l^{-} (a q .)$
When we dissolve $N a C l$ in $H_{2} O$ it dissociates into ions. The reaction is as given below:
$N a C l + H_{2} O ⇄ {N a}^{+} (a q .) + {C l}^{-} (a q .)$

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Similar questions

N a C l (s) + a q ⟶ N a^{\oplus} (a q) + C l^{⊖}

Δ H = 3.9 k J

N a^{\oplus} (g) + C l^{⊖} (g) ⟶ N a C l (s) Δ H = - 788 k J

C l^{⊖} (g) + a q ⟶ C l^{⊖} (a q) Δ H = - 394.1 k J

Then the enthalpy of hydration of

N a^{\oplus}

Q. Assertion :On dissolving

N a C l

in water we get

N a^{+} (a q .)

C l^{-} (a q .)

in the solution but

H C l

H_{3} O^{+}

C l^{-}

N a C l

H C l

Q. How can be equilibrium concentration of

A g^{+}

can be reduced in a solution of

N a^{+}, C l^{+}, A g^{+}

N O_{3}

, in contact with solid

A g C l

N a^{+} (a q) + C l (a q) + A g^{+} (a q) + N O_{3} (a q) ⇌ A g C l (s) + N a^{+} (a q) + N O_{3} (a q) Δ H = 65.9 k J

Q. ways in which the equilibrium concentration of

A g^{+}

can be reduced in a solution of

N a^{+}

C l^{-}

A g^{+}

N O_{3}^{-}

, in contact with solid

A g C l .

N a^{+} (a q) + C l^{-} (a q) + A g^{+} (a q) + N O_{3}^{-} (a q) ⇌ A g C l (s) + N a^{+} (a q) + N O_{3}^{-} (a q) Δ H = - 65.9 k J

Q. What type of crystal defect is indicated in the diagram below?

$N a^{+}$	$C l^{-}$	$N a^{+}$	$C l^{-}$	$N a^{+}$	$C l^{-}$
$C l^{-}$		$C l^{-}$	$N a^{+}$		$N a^{+}$
$N a^{+}$	$C l^{-}$		$C l^{-}$	$N a^{+}$	$C l^{-}$
$C l^{-}$	$N a^{+}$	$C l^{-}$	$N a^{+}$		$N a^{+}$

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