What are the roots of the quadratic equation $(x + 2)^{2}$ -16 = 0?

$x$ = 2 or -6

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$x$ = -2 or 6

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$x$ = 2 or 6

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$x$ = -2 or -6

No worries! We‘ve got your back. Try BYJU‘S free classes today!

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Solution

The correct option is A
$x$ = 2 or -6

$(x + 2)^{2} - 16 = 0$

$(x + 2)^{2} = 16$

$(x + 2) = \sqrt{16}$

$(x + 2) = + 4 o r (x + 2) = - 4$

$x$ = 2 or $x$ = - 6

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