Question

What are the roots of the quadratic equation $(x+2{)}^2$-16 = 0?

• A. $x$ = 2 or -6
• B. $x$ = -2 or 6
• C. $x$ = 2 or 6
• D. $x$ = -2 or -6

Answer 1

The correct option is A

$x$ = 2 or -6

$(x+2{)}^2-16=0$

$(x+2{)}^2=16$

$(x+2)=\sqrt{16}$

$(x+2)=+4or(x+2)=-4$

$x$ = 2 or $x$ = - 6